The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. a 1.501 g1.501 g sample of ether was combusted in an oxygen rich environment to produce 3.565 g3.565 g of co2(g)co2(g) and 1.824 g1.824 g of h2o(g)h2o(g) . insert subscripts to complete the empirical formula of ether. empirical formula: cho

The empirical formula of the ether will be

Explanation:

The chemical equation for the combustion of ether follows:

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of

Mass of

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 3.565 g of carbon dioxide, of carbon will be contained.

In 18g of water, 2 g of hydrogen is contained.

So, in 1.824 g of water, of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

Moles of Carbon =

Moles of Hydrogen =

Moles of Oxygen =

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0204 moles.

For Carbon =

For Hydrogen  =

For Oxygen  =

The ratio of C : H : O = 4 : 10 : 1

Hence, the empirical formula for the given compound is

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .

0.88m hope i am correct : )