How many ml of 0.100 m nahco3 are needed to prepare 750.0ml of a 0.0500 m nahco3 solution

Following the rule of thumb in dilution, the equation that can be used to solve this problem is:

C1V1 = C2V2

where:
C1 = concentration of solution 1
V1 = volume of solution 1
C2 = concentration of solution 2
V2 = volume of solution 2

(0.1)(V1) = (0.05)(750)
V1 = 375 mL

This shows that 375 mL of a 0.1 m NaHCO3 solution is needed in order to dilute it to a 0.05 m NaHCO3 solution of 750 mL.