Chemistry, 28.01.2020 03:31 lyn36

Give the theoretical yield, in grams, of co2 from the reaction of 4.000 moles of c8h18 with 4.000 moles of 02 2 c8h18 25 02 16 co2+ 18 h20

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Answer from: tinajackson6534

Answer : The theoretical yield of CO_2 is, 112.64 grams.

Explanation : Given,

Given moles of $C_8H_{18}$ = 4 moles

Given moles of O_2 = 4 moles

Molar mass of CO_2 = 44 g/mole

First we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

From the given balanced reaction, we conclude that

As, 25 moles of O_2 react with 2 moles of $C_8H_{18}$

So, 4 moles of O_2 react with $\frac{2}{25}\times 4=0.32$ moles of $C_8H_{18}$

From this we conclude that, $C_8H_{18}$ is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent because it limits the formation of product.

Now we have to calculate the moles of CO_2 .

As, 25 moles of O_2 react to give 16 moles of CO_2

So, 4 moles of O_2 react to give $\frac{16}{25}\times 4=2.56$ moles of CO_2

Now we have to calculate the mass of CO_2 .

$\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2$

$\text{Mass of }CO_2=(2.56mole)\times (44g/mole)=112.64g$

Therefore, the theoretical yield of CO_2 is, 112.64 grams.

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Give the theoretical yield, in grams, of co2 from the reaction of 4.000 moles of c8h18 with 4.000 mo...

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