Determine the theoretical yield of hcl if 60.0 g of bc13 and 37.5 g of h20 are reacted according to the following balanced reaction. a possibly useful molar mass is bc13 117.16 g/mol. bc13(g)+3 h20(1) -- h3bo3(s)+3 hc1(g)

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of = 60 g

Mass of = 37.5 g

Molar mass of = 117 g/mole

Molar mass of = 18 g/mole

Molar mass of = 36.5 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 1 mole of react with 3 mole of

So, 0.513 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of .

As, 1 mole of react to give 3 moles of

So, 0.513 moles of react to give moles of

Now we have to calculate the mass of .

Therefore, the theoretical yield of HCl is, 56.1735 grams

m=9

step-by-step explanation: