Glucose (c6h12o6) is an important biological molecule.
(round the answer to nearest hundredth.)
what is the percent by mass of carbon in glucose?

40.0%.

Explanation:

∴ The percent by mass of carbon in glucose = [(The atomic mass of C in glucose)/(The molar mass of glucose)] x 100 = [(72.0 g/mol)/(180 g/mol)] x 100 = 40.0%.

the answer is 303.15 or 303

some sources quote the lethal dose, for an average 170lbs opiate-naive individual is between 75 and 375 mg