Suppose you are investigating the reaction: m(s) + 2 hcl(aq) → mcl2(aq) + h2(g). you weigh out a 0.295 gram piece of metal and combine it with 65 ml of 1.00 m hcl in a coffee-cup calorimeter. if the molar mass of the metal is 57.78 g/mol, and you measure that the reaction absorbed 104 j of heat, what is the enthalpy of this reaction in kj per mole of limiting reactant? enter your answer numerically to three significant figures in units of kj/mol.

The enthalpy of the reaction is

Explanation:

To calculate the number of moles, we use the equation:

  ....(1)

Given mass of metal = 0.295 g

Molar mass of metal = 57.78 g/mol

Putting values in above equation, we get:

We are given:

Volume of hydrochloric acid = 65 mL = 0.065 L   (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 1 moles/ L

Putting values in above equation, we get:

By Stoichiometry of the reaction:

1 mole of metal reacts with 2 moles of hydrochloric acid..

So, 0.0051 moles of metal will react with = of hydrochloric acid.

As, given amount of hydrochloric acid is more than the required amount. So, it is considered as an excess reagent.

Thus, metal is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

If 1 mole of metal absorbs 104 J of heat

Then, 0.0051 moles of metal will absorb = of heat.

Converting joules to kilo joules, we use the conversion factor:

Converting the given value in kilo joules, we get:

Hence, the enthalpy of the reaction is

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i