When 9.6 grams of nabr are dissolved in enough water to create a 165 gram solution what is the concentration expressed as a percent by mass

5.8 %

Explanation:

% by mass = (mass of solute/mass of solution) × 100 %

Data:

    Mass of NaBr =    9.6 g

Mass of solution = 165    g

Calculation:

% by mass = (9.6 g/165 g) × 100 % = 5.8 %

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answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole