Fill in the coefficients that will balance the following reaction: a0cr2(so4)3 + a1agno3 -> a2cr(no3)3 + a3ag2so4

Answer

Explanation:

can you please put it in boxes so i can find out the answer

a0=1

a1=6

a2=2

a3=3

Explanation:

We have to start with the reaction:

We have to start with "". If we want to balance Cr we have to obtain 2 on both sides. Therefore we have to add a "2" on the right side, so:

Then we can balance "" as a whole. We have 6 on the right, we have to have the same amount on the left side, so:

Then we can balance "". We have 6 on the left, so we have to have the same amount on the right if we already have 2 we have to put a · in front (on the right side) to obtain in total 6, so:

Finally, when we add this last number the we will have 3 on both sides. Therefore the reaction is already balanced.

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.