Calculate the molarity of each of the following solutions. part a) 0.12 mol of lino3 in 5.5 l of solution part b) 60.7 g c2h6o in 2.48 l of solution part c) 14.2 mg ki in 100 ml of solution

For A: The molarity of solution is 0.218 M.

For B: The molarity of solution is 0.532 M.

For C: The molarity of solution is

Explanation:

Molarity is defined as the number of moles present in one liter of solution.

Mathematically,

Or,

We are given:

Moles of = 0.12 moles

Volume of the solution = 5.5 L

Putting values in above equation, we get:

Hence, the molarity of solution is 0.0218 M.

We are given:

Given mass of = 60.7 g

Molar mass of = 46 g/mol

Volume of the solution = 2.48 L

Putting values in above equation, we get:

Hence, the molarity of solution is 0.532 M.

We are given:

Given mass of KI = 14.2 mg =     (Conversion factor:

Molar mass of KI = 166 g/mol

Volume of the solution = 100 L

Putting values in above equation, we get:

Hence, the molarity of solution is

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