According to the following balanced reaction, how many moles of hno3 are formed from 8.44 moles of no2 if there is plenty of water present? 3 no2(g) + h2o(l) → 2 hno3(aq) + no(g)

Considering the definition of reaction stoichiometry, 5.63 moles of HNO₃ are formed from 8.44 moles of NO₂ if there is plenty of water present.

The balanced reaction is:

3 NO₂ + H₂O → 2 HNO₃ + NO

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

So, you can apply the following rule of three: if by reaction stoichiometry 3 moles of NO₂ produce 2 moles of HNO₃, 8.44 moles of NO₂ produces how many moles of HNO₃?

amount of moles of HNO₃= 5.63 moles

Finally, 5.63 moles of HNO₃ are formed from 8.44 moles of NO₂ if there is plenty of water present.

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5.63 mol.

Explanation:

3NO₂(s) + H₂O(l) → 2HNO₃(aq) + NO(g),

It is clear that 3 mol of NO₂ reacts with 1 mol of H₂O to produce 2 mol of HNO₃ and 1 mol of NO.

Water is present as an excess reactant and NO₂ is limiting reactant.

3 mol of NO₂ produces → 2 mol of HNO₃, from stichiometry.

8.44 mol of NO₂ produces → ??? mol of HNO₃.

∴ The no. of moles of HNO₃ are formed = (8.44 mol)(2 mol)/(3 mol) = 5.63 mol.

c. 75.7

i think that is the right