For the following reaction, 3.70 grams of oxygen gas are mixed with excess carbon monoxide . the reaction yields 8.25 grams of carbon dioxide . carbon monoxide(g) + oxygen(g) carbon dioxide(g) what is the ideal yield of carbon dioxide? grams what is the percent yield for this reaction? %

81% Yield

Explanation:

2CO        +               O₂                                =>     2CO₂

Excess                3.70g O₂                          =>     8.25g CO₂ (actural yield)

               (3.70g O₂)/(32g O₂/mol O₂)

                   = 0.1156 mol O₂                       =>  2(0.1156) mol CO₂

                                                                          = 10.175g (Theoretical Yield)

%Yield = (Actual Yield / Theoretical Yield)100%  

= (8.25g/10.175g)100% = 81% Yield

here are some of the ways in which chemical and nuclear reactions differ.

explanation: