A5.91 g unknown sample analyzed by elemental analysis revealed a composition of 37.51 % c. in addition, it was determined that the sample contains 1.4830 × 1023 hydrogen atoms and 1.2966 × 1023 oxygen atoms. what is the empirical formula?

C₆H₈O₇

Explanation:

1) Calculate the mass of carbon (C)

mass of C = % of C × mass of sample / 100mass of C = 37.51% × 5.91 g / 100 = 2.21 g

2) Calculate the number of moles of C

number of moles = mass in grams / molar massnumber of moles of C = 2.21 g / 12.01 g/mol = 0.184 moles

3) Calculate the number of moles of hydrogen atoms, H:

number of moles = number of atoms / Avogadro's numbernumber of moles of H = 1.4830 × 10²³ / 6.022 × 10²³ = 0.24626 moles

4) Calculate the number of moles of oxygen atoms, O:

number of moles = number of atoms / Avogadro's numbernumber of moles of O = 1.2966 × 10²³ / 6.022 × 10²³ = 0.21531 moles

5) Find the mole ratios:

Summary of moles:

C: 0.184 molH: 0.24626 molO: 0.21531 mol

Divide every amount by the smallest number, which is 0.184:

C: 0.184 / 0.184 = 1H: 0.24626 / 0.184 = 1.34O: 0.21531 / 0.184 = 1.17

Multiply by 3 to round to integer numbers:

C:  1 × 3 = 3H: 1.34 × 3 = 4.02 ≈ 4O: 1.17 × 3 = 3.51

Multiply by 2 to round to integer numbers:

C:  3 × 2 = 6H: 4 × 2 = 8O: 3.51 × 2 ≈ 7

Use the mole ratios as superscripts to write the empirical formula

C₆H₈O₇ ← answer

Just as a reference, you can search in internet and find that one compound with that empirical formula is citric acid.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !