Will vote can someone me with the empirical formula of c: 46.66% h: 4.48% n: 31.10% o: 17.76% i am getting 3c 4h 2n 1o but this is not one of the options so i don’t know if i’m doing it wrong or the question is wonky because i did all the others right

The answer is C7H8N4O2.

Same problem as your other question - you rounded in a place where you shouldn't have (see explanation below, exact same process)!

Explanation:

These are percents by mass. Pretend you have a 100g sample. That means you have:

46.66g C

4.48g H

31.10g N

17.76g O

Divide each by molar mass to find the moles of each:

C: 46.66 / 12 = 3.89 mol

H: 4.48 / 1 = 4.48 mol

N: 31.10 / 14 = 2.22 mol

O: 17.76 / 16 = 1.11 mol

Now divide each of these values by the lowest of the three to find the ratio between each element in the compound:

C: 3.89 / 1.11 ≈ 3.5

H: 4.48 / 1.11 ≈ 4

N: 2.22 / 1.11 = 2

O: 1.11 / 1.11 = 1

As with your other question, 3.5 is too different from 3, so you can't round it down. The .5 makes it easy to find the LCD - it's 2. Multiply each of the numbers by 2 to get your final

C: 3.5 x 2 = 7

H: 4 x 2 = 8

N: 2 x 2 = 4

O: 1 x 2 = 2

Again, if you were to take the percent masses of the empirical formula you came up with, you'll see they're quite different from the one the question provided, which is why you can't round in this situation.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: