If you have 35.0g of na and 100.0g of cl2, what is the maximum amount of nacl that you can produce? 2na + cl2 → 2nacl 57.7 g 165 g 75.8g 89.0 g

89.0 g.

Explanation:

2Na + Cl₂ → 2NaCl,

It is clear that 2 mol of Na react with 1 mol of Cl₂ to produce 2 mol of NaCl.

no. of moles of Na = mass/molar mass = (35.0 g)/(22.989 g/mol) = 1.522 mol.

no. of moles of Cl₂ = mass/molar mass = (100.0 g)/(70.906 g/mol) = 1.41 mol.

From the balanced equation: Na reacts with Cl₂ with (2: 1) molar ratio.

∴ 1.522 mol of Na "limiting reactant" reacts completely with 0.761 mol of Cl₂ "excess reactant".

2 mol of Na produces → 2 mol of NaCl, from stichiometry.

∴ 1.522 mol of Na produces → 1.522 mol of NaCl.

∴ The mass of the produced salt (NaCl) = (no. of moles)(molar mass) = (1.522 mol)(58.44 g/mol) = 88.95 g ≅ 89.0 g.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

answer: option (a) is the correct answer.

explanation:

the measurement of hydrogen ions in a solution is known as ph.

if ph of a solution is less than 7 then the solution is acidic. if ph of a solution is greater than 7 then the solution is basic.

when the ph of a solution equals 7, then the solution is considered as neutral.

the ph of pure water is 7, therefore, it means that concentration of hydronium ions equals that of hydroxide ions.