A14.0 ml sample of acetic acid requires 28.23 ml of a 0.521 m solution of naoh for titration to the equivalence point. what is the concentration of the acetic acid?

Concentration of the acid = 1.05M

Explanation:

Given parameters:

Volume of acid = 14.0mL = 0.014L

Volume of base = 28.23mL = 0.02823L

Concentration of the base = 0.521M

Unkown:

Concentration of acid = ?

The reaction equation is given below:

          CH₃COOH + NaOH → CH₃COONa + H₂O

To obtain the unknown concentration of the acid used in the reaction, we simply work from the known parameters of the given base.

Procedure:

       Number of moles of base = concentration of base x volume

      Number of moles of base = 0.521 x 0.02823 = 0.0147mol

      1mole of the base neutralize on mole of acid,

    Therefore, 0.0147mol of the acid would be neutralized by the base.

To find the concentration of the acetic acid,

Concentration of acid =

Concentration of acid =

Concentration of the acid = 1.05M

convalent bond :

is a chemical bond formed by the sharing of electron between 2 atoms.

it is the direct chemical bond between 2 atoms.

in bond formation atoms are involved here.

electrovalent bond:

is a chemical bond defined as electroststic attraction between 2 atoms.

it is the electrostatic attraction between 2 atoms.

in bond formation, ions are involved here.

hope it

and ur welcm

: )

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)