In a constant‑pressure calorimeter, 60.0 ml of 0.300 m ba(oh)2 was added to 60.0 ml of 0.600 m hcl. the reaction caused the temperature of the solution to rise from 23.65 ∘c to 27.74 ∘c. if the solution has the same density and specific heat as water ( 1.00 g/ml and 4.184j/g⋅k,) respectively), what is δ for this reaction (per mole h2o produced)? assume that the total volume is the sum of the individual volumes.

ΔH = 57.04 Kj/mole H₂O

Explanation:

60ml(0.300M Ba(OH)₂(aq) + 60ml(0.600M HCl(aq)

=> 0.06(0.3)mole Ba(OH)₂(aq) + 0.60(0.6)mole HCl(aq)

=> 0.018mole Ba(OH)₂(aq) + 0.036mole HCl(aq)

=> 100% conversion of reactants => 0.018mole BaCl₂(aq) + 0.036mole H₂O(l) + Heat

ΔH = mcΔT/moles H₂O <==> Heat Transfer / mole H₂O

=(120g)(4.0184j/g°C)(27.74°C - 23.65°C)/(0.036mole H₂O)

ΔH = 57,042 j/mole H₂O = 57.04 Kj/mole H₂O

i do not get it   at all