If you had a 0.5 m kcl solution, how much solute would you have in moles, and what would the solute be? since kcl has a molecular weight of 74.5, how many grams/l would this be?

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) → c2h2 (g) + caoh2 (s) =δh−414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) → 5ch2chco2h (g) =δh132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .

What element has similar physical and chemical properties as boron.

Find the missing probability in the table below a.0.10 b.40 c.0.80 d. 0.20