During an experiment, 95 grams of calcium carbonate reacted with an excess amount of hydrochloric acid. if the percent yield of the reaction was 82.15%, what was the actual amount of calcium chloride formed? caco3 + hcl → cacl2 + co2 + h2o 105.3 grams 101.1 grams 95.6 grams 86.5 grams

Actual yield: 86.5 grams.

Explanation:

How many moles of formula units in 95 grams of calcium carbonate ?

Refer to a modern periodic table for relative atomic mass data:

Formula mass of :

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.

How many moles of will be produced?

The coefficient in front of in the chemical equation is the same as that in front of . That is:

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What's the theoretical yield of calcium chloride? In other words, what's the mass of of ?

Again, refer to a periodic table for relative atomic data:

.

.

What's the actual yield of calcium chloride?

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.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)