67.4 l of sulfur dioxide (so2) gas at 0.0c and at 1 atm of pressure is equivalent aren’t to how many moles?

Solution here,

Volume(V)=67.4 L

Pressure(P)=1 atm

Temperature(T)=(0+273)K=273K

Universal gas constant(R)=0.0821 L.atm.mol^-1K^-1

No. of moles(n)=?

Now,

PV=nRT

or, 1×67.4=n×0.0821×273

or, 67.4=22.4n

or, n=67.4/22.4

or, n=3

therefore, required no. of mole is 3.

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

the answers would be

the first one and the second one