Iodine, i2, has many uses, including the production of dyes, antiseptics, photographic film, pharmaceuticals, and medicinal soaps. it forms when chlorine, cl2, reacts with iodide ions in a sodium iodide solution. which of the following half-reactions for this oxidation‑reduction reaction describes the oxidation, and which one describes the reduction? cl2 + 2e‒ → 2cl‒ 2i‒ → i2 + 2e‒

2I ⁻ → I₂ + 2e⁻ describes the oxidation.Cl₂ + 2e⁻ → 2Cl ⁻ describes the reduction.

Explanation:

Oxidation-reduction reaction is the simulaneous oxidation and reduction of the substances and is represented by two half-reactions.

The oxidation half-reaction is the loss of electrons, with the consequent increase in the oxidation state by the oxidized substance.

In this case, the process that shows the loss of electrons is:

2I⁻ → I₂ + 2e⁻

That reaction shows:

Two I⁻ ions lose two electrons (one each) to be oxidized to I₂.The change in the oxidation number is from -1 to 0.Hence this half-reaction is the oxidation reaction.

On the other hand, the reduction half-reaction is the gain of electrons, with the consequent reduction of the oxidation state by the reduced substance.

In this case, the process that shows the gain of electrons is:

Cl₂ + 2e⁻ → 2Cl⁻

That reaction shows:

Two Cl atoms gain two electrons (one each) to be reduced to Cl⁻.The change in the oxidation number is from 0 to - 1.Hence, this half-reaction is the reduction reaction.

Summary:

2I ⁻ → I₂ + 2e⁻ describes the oxidation.Cl₂ + 2e⁻ → 2Cl ⁻ describes the reduction.

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