A275 g sample of nickel at 100.0°c is placed in 100.0ml of water at 22.0°c, what is the final temperature of the water? (specific heat capacity of nickel = 0.444j/g°c)

275 x 0.444 ( T - 100) + 100 x 4.18 ( T - 22)=0

122.1 T - 12210 + 418 T - 9196 =0

540.1 T = 21406

T = 39.6 °C

1 a

2 d

3 a

4 c

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml