C3h8(g) + 2o2(g) → 4h2o(g) + 3co2(g) δhreaction=2,220 kj/mol calculate the enthalpy of combustion for 24.5g propane given the molecular weight of propane is 44.097 g/mol. a) 723 kj b) 1,010 kj c) 1,230 kj d) 2,390 kj

Option C) 1,230 kJ

Explanation:

According to the data, 1 mol of propane liberates 2,220 kJ of energy when it is combusted. If we have 24.5 g of propane, this mass is equal to 0,56 mol (of propane):

44.097 g of propane>1 mol

24.5 g of propanex= 0.56 mol

Then, the enthalpy of the described chemical reaction (propane´s combustion) is 2,220 kJ when 1 mol of propane is combusted, so:

1 mol propane>2,220 kJ of energy

0.56 mol propane (24.5 g)x= aproximately 1,24 kJ (which would be option C)

the correct option is c.

isotopes refers to different forms of the same element with the same atomic number but different mass number as a result of difference in their neutron numbers. isotopes have different relative atomic mass but share the same chemical properties.

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