Value: 1.66 points 2 attempts left check my work enter your answer in the provided bor. calculate the height of a column of ethylene glycol (ch(oh)ch(oh)) that would be supported by atmospheric pressure. the density of ethylene glycol is 1.112 g/cm

Explanation:

The pressure p exerted by a column of liquid is given by the formula  

p = hρg

where

h = height of column

ρ = density of liquid

g = acceleration due to gravity

Data:

p = 1 bar = 100 kPa = 10⁵ N·m⁻² = 10⁵ kg·m⁻¹s⁻²

ρ = 1.112 g·cm⁻³ = 1112 kg·m⁻³

g = 9.807 m·s⁻²

Calculation:

10⁵ = h × 1112 × 9.807

10⁵ = 1.091 × 10⁴ h

h = 9.170 m