What is the concentration of a solution that has a volume of 2.5l and contains exactly 2.125 moles of calcium phosphate

0.85 mol/L.

Explanation:

M = (no. of moles of solute)/(Volume of the solution (L))

no. of moles of calcium phosphate = 2.125 mol.

Volume of the solution = 2.5 L.

∴ M of calcium phosphate = (2.125 mol)/(2.5 L) = 0.85 mol/L.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

answerca air mass;