Aballoon filled with air has volume of 4.24 liters at 23.00°c if the balloon is cooked at constant pressure to 5.00°c what is it’s new volume? the balloons volume at 5°c is liters

pV = nRT , or  V = \frac{nRT}{p} , with p - pressure, V - volume, n - amount of substance, T - temperature in K.

Then:  \frac{V_2}{V_1} = \frac{n_2RT_2p_1}{p_2n_1RT_1}  

n_2 = n_1 ,  p_2 = p_1  

V_2 = V_1 \cdot \frac{T_2}{T_1} = 4.24 \frac {(273.00+5.00)}{(273.00+23.00)}=3.98 l   Explanation

The new  volume is calculated using the Charles law formula

that is V1/ T1 = V2/T2  where,

V1 = 4.24 l

T1= 23c  into kelvin = 23  +273 =296 K

T2 = 5.00 c into kelvin = 5.00 + 273 = 278 K

V2 = ?

by making  V2 subject the subject of the formula  by multiplying both side by T2

V2 = V1 xT2/ T1

V2 =  (4.24 L   x 278 K)  / 296 k  =3.98 L

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Explanation:

Explanation:

They need to receive commands from Earth and send the data they collect back to Earth. ... These radio dishes also receive the information sent to Earth by the spacecraft. NASA spacecraft operating well out of Earth's orbit use the Deep Space Network (DSN).

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )