A4.5-liter sample of a gas at 2.0 atm and 300.0 k has 0.80 mole of the gas. if 0.35 mole of the gas is added to the sample at the same temperature and pressure, what is the final volume of the gas? \

The final volume = 6.469 L.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(V₁n₂) = (V₂n₁)

V₁ = 4.5 L, n₁ = 0.8 mol.

V₂ = ??? L, n₂ = 0.8 mol + 0.35 mol = 1.15 mol.

∴ V₂ = (V₁n₂)/n₁ = (4.5 L)(1.15 mol)/(0.8 mol) = 6.469 L.

Also 6.5

Explanation:

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