Asap
for the reaction 2h2(g) + s2(g)< > 2h2s(g), determine the equilibrium constant at 700oc if at this temperature, the equilibrium concentrations are as follows:
[h2] = 0.208 m, [s2] = 1.13 × 10-6 m , [h2s] = 0.725 m
a) 1.08 × 107
b) 3.49
c)4.55 × 10-7
d)3.22 × 106
e)441

Equilibrium constant of a reaction is the ratio of concentrations of the products and the reactants when the reaction is in equilibrium. This value is independent of the concentrations since the conditions are at equilibrium instead it depends on ionic strength and temperature.

First, we write the equilibrium expression.

K = [H2S]^2 / [H2]^2 x [S2]
K = (0.725^2) / [(0.208^2) (1.13 x 10^-6)]
K = 10751545.56 or 1.08 x 10^7

Thus, the answer is A.

Answer trigonal pyramidal;