An ethylene gas torch requires 3200 l of gas at 3.00 atm what will be the pressure of the gas if ethylene is supplied by a 250.0 l tank?

38.4L

Explanation:

Given parameters of the ethylene gas:

Initial Volume V₁ = 3200L

Initial pressure P₁ = 3atm

Final Volume V₂ = 250L

Final pressure P₂ = ?

We need information about the unknown final pressure.

Based on the given parameters, we can apply Boyle's law. The law states that "the volume of a fixed mass of a gas is inversely proportional as the pressure changes if temperature is constant".

NB: We assume that the torch provides a constant source of heat.

The law is expressed mathematically as:

P₁V₁ = P₂V₂

Making the unknown P₂ the subject of the equation gives:

P₂ = P₁V₁ / V₂

P₂ = 3200x3/250

P₂ = 9600/250

P₂ = 38.4L

Pressure of the gas = 38.4L

i believe the answer is a.