Identify whether each process is either oxidation or reduction:
al → al3+ + 3 e-
s2- → s + 2 e-
cu → cu2+ + 2 e-

show all work.

Al → Al³⁺ + 3 e⁻,     is an oxidation process.

S²⁻ → S + 2 e⁻,        is an oxidation process.

Cu → Cu²⁺ + 2 e⁻,    is an oxidation process.

Explanation:

The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).The oxidation process is the process in which electrons are lost and produce positively charged ions.The reduction process is the process in which electrons is gained and negatively charge ions are produced.

So,

Al → Al³⁺ + 3 e⁻,     is an oxidation process.

Al loses 3 electrons and produce Al³⁺c

S²⁻ → S + 2 e⁻,        is an oxidation process.

S²⁻ loses 2 electrons and produce S.

Cu → Cu²⁺ + 2 e⁻,    is an oxidation process.

Cu loses 2 electrons and produce Cu²⁺.

Ais the correct answer