A4.5 liter sample of a gas at 2 atm and 300 k has 0.80 mole of gas. if 0.35 mole of the gas is added to the sample at the same temperature and pressure, what is the volume of the gas?

3.9 liters
5.3 liters
6.3 liters
6.5 liters

6.5 liters.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

(V₁n₂) = (V₂n₁)

V₁  = 4.5 L, n₁ = 0.80 mol,

V₂  =  ??? L, n₂ = 0.35 + 0.80 = 1.15 mol.

(V₁n₂) = (V₂n₁)

∴ V₂ = (V₁n₂)/n₁ = (4.5 L)(1.15 mol)/(0.8 mol) = 6.469 L ≅ 6.5 L.

So, the right choice is: 6.5 liters.

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

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