*if youre good at chemistry * * will mark you brainliest with 25 points *

the graph shows the amount of a gaseous product formed over time during two trials of a reaction. a different concentration of a reactant was used during each trial while other factors were kept constant.

a graph is shown with two graph lines sloping upwards. the title on the x axis is time and the title on the y axis is amount of product. the graph line with a steeper slope is labeled trial 2 and the other is labeled trial 1.

which of the following statements explains which trial has a higher concentration of the reactant?

trial 1, because the final amount of product formed is higher.
trial 1, because this reaction lasted for a longer duration than trial 2.
trial 2, because this reaction was initially fast and slowed down later.
trial 2, because the amount of product formed per unit time is higher.

The answer is C-Trial 2, because this reaction was initially fast and slowed down later

Explanation:

With a higher concentration, there is a higher chance of particles colliding together to form reactions. So that means reactions will form faster

Trial 2, because the amount of product formed per unit time is higher.

Explanation:

In a gas reaction, it is possible to find which reaction has a higher concentration of reactants for collision theory.

This theory says that a reaction occurs when the reactants gives an effective collision.

The number of effective collisions is proportional to initial concentration of reactants. That is, the higher initial concentration, the higher effective collisions.

Also, the rate of a chemical reaction is proportional to the number of collisions between reactant molecules. That means your reaction will be faster if the number of effective collisions is high.

Now, if you see the graph, trial 2 is faster than trial 1. That means trial 2 has a higher concentration of reactant that trial 1 because the amount of product formed per unit time is higher.

I hope it helps!

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.