Compare the energies of excitation and emission for fluorescence. which is greater and why?

The excitation energy is always greater than the emission energy .

Explanation:

When a molecule absorbs energy, electrons are excited from the ground state (S₀) to different vibrational levels of the excited state (S₁) in about 1 fs.

In the next picosecond, most of them will drop to the lowest vibrational level of S₁.

They remain there for about 10 ns, and then they drop to different vibrational levels of S₀.

The excitation energy is always greater than the emission energy because excitation occurs from the ground state of S₀ to a higher vibrational level of S₁, while emission occurs from the lowest vibrational level of S₁ to a higher vibrational of S₀.

no

explanation:

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :