Calculate the mass defect and the binding energy/nucleon of the nuclide^9 4 be, which has a mass of 9.012 182 24 amu. the mass of a proton is 1.007 276 47 amu and the mass of a neutron is 1.008 664 90. one amu = 1.6605 x 10^-27 kg and the speed of light is 3.00 x 10^8 m/s.

m(94Be) = 9.012 182 24 amuN(protons) = 4N(neutrons) = 9 – 4 = 5m(protons) = (4 protons) (1.007 276 47 amu/proton) = 4.029 105 88 amum(neutrons) = (5 neutrons) (1.008 664 90 amu/neutron) = 5.043 324 50 amum(protons) + m(neutrons) = 4.029 105 88 amu + 5.043 324 50 amu = 9.072 430 38 amuMass defect m = 9.072 430 38 amu – 9.012 182 24 amu = 0.060 248 14 amum = (0.060 248 14 amu/nucleus) (1.6605 10-27kg/amu) = 1.0004 10-28 kg/nucleusE =mc2= (1.0004 10-28 kg/nucleus) (3.00 108m/s)2= 9.0038 10-12J/nucleusN(nucleons)= N(protons)+N(neutrons) = 9E =(9.0038 10-12J/nucleus) (1 nucleus/9nucleons) =1.0004 10-12J/nucleon2.