How much o2 reacts completely with 4.0 moles of ch3oh in the reaction 2 ch3oh + 3 o2 → 2 co2 + 4 h2o ?

= 6.0 moles

Explanation:

The equation for the reaction is;

2 CH3OH + 3 O2 → 2 CO2 + 4 H2O

We are given 4.0 moles of CH3OH.

From the reaction; 2 moles of CH3OH requires 3 moles of O2,

Therefore; moles of Oxygen will be;

= 4.0 moles × 3/2

= 6.0 moles

Therefore; 6.0 moles of Oxygen gas are required to react completely with 4.0 moles CH3OH.