The activation energy of a certain reaction is 40.1 kj/mol . at 26 ∘c , the rate constant is 0.0160s−1. at what temperature in degrees celsius would this reaction go twice as fast? express your answer with the appropriate units. view available hint(s)

Explanation:

We can use the Arrhenius equation:

Data:

Eₐ = 40.1 kJ·mol⁻¹

k₁ = 0.0160 s⁻¹;              k₂ = 0.0320 s⁻¹

T₁ = 26 °C = 299.15 K; T₂ = ?  

Calculations:

T₂ = 312.6 K = 39 °C

The reaction will go twice as fast at .

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