How much heat is required to raise the temperature of 1.248kg of gold from 22.0°c to 45.0°c(c=0.129j/g°c)

= 3,702.816 Joules

Explanation:

Heat absorbed by water is equivalent to heat released by copper.

Heat absorbed is given by:

Q = mcΔT

where m is the mass, c is the specific capacity and ΔT is the change in temperature.

Mass = 1248 g

ΔT = 45°C - 22°C = 23°C

c = 0.129j/g°c

Heat = 1248 g × 23°C × 0.129j/g°C

        = 3,702.816 Joules

is there multiple choice answers?

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