Use the free energies of formation given below to calculate the equilibrium constant (k) for the following reaction at 298 k. 2 hno3(aq) + no(g) → 3 no2(g) + h2o(l) k = ? δg°f (kj/mol) -110.9 87.6 51.3 -237.1 use the free energies of formation given below to calculate the equilibrium constant (k) for the following reaction at 298 k. 2 hno3(aq) + no(g) → 3 no2(g) + h2o(l) k = ? δg°f (kj/mol) -110.9 87.6 51.3 -237.1 0.980 1.02 1.15 × 10-9 5.11 × 10-4 8.71 × 108

K = 1.15 x 10⁻⁹.

Explanation:

ΔG°rxn = - RTlnK.

where, ΔG°rxn is the standard free energy change of the reaction.

R is the general gas constant (R = 8.314 J/mol.K).

T is the temperature of the reaction (K) (T = 298.0 K).

K is the equilibrium constant.

ΔG°rxn = ΣG°f, products – ΣG°f, reactants

ΔG°rxn = [3(G°f, NO₂) + (G°f, H₂O)] - [2(G°f, HNO₃) + (G°f, NO)]

ΔG°rxn = [3(51.3 kJ/mol) + (- 237.1 kJ/mol)] - [2(- 110.9 kJ/mol) + (87.6 kJ/mol)

ΔG°rxn = (- 83.2 kJ/mol) - (- 134.2 kJ/mol) = 51.0 kJ/mol.

∵ ΔG°rxn = - RTlnK.

∴ lnK = - (ΔG°rxn)/(RT) = - (51000 J/mol)/(8.314 J/mol.K)(298.0 K) = - 20.58.

∴ K = 1.15 x 10⁻⁹.

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.