What is the mass in grams of 0.257 mol of sucrose (c12h22o11)?

87.894 grams.

Explanation:

So we know that the mass of the carbon is 12g, the Mass of the Hydrogen is  1g and the Mass of the Oxygen is 16g. Given, Chemical Formula of the Sucrose C₁₂H₂₂o₁₁ we can calculate the molar mass by performing the following operation:

Molar Mass = 12 × 12 + 1 × 22 + 16 × 11 = 144 + 22 + 176 = 342 g/mole

So if we need to know the mass in grams of 0.257 mol, then we have to:

342 g/mole * 0.257 mol = 87.894 grams.

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.