The following reaction shows sodium hydroxide reacting with sulfuric acid.

naoh + h2so4 → na2so4 + h2o

how many grams of na2so4 are produced from 10.0 grams of naoh?

(molar mass of na = 22.989 g/mol, o = 15.999 g/mol, h = 1.008 g/mol, s = 32.065 g/mol)

17.8 grams
19.2 grams
35.5 grams
38.5 grams

The mass of produced will be 17.8 grams.

Explanation:

To calculate the number of moles, we use the equation:

 ....(1)

For Sodium hydroxide:

Given mass of sodium hydroxide = 10 g

Molar mass of

Putting values in above equation, we get:  

For the given chemical equation:

By Stoichiometry of the reaction:

2 moles of sodium hydroxide produces 1 mole of sodium sulfate.

So, 0.25 moles of sodium hydroxide will produce = of sodium sulfate.

Now, to calculate the mass of sodium sulfate, we use equation 1:

Moles of sodium sulfate = 0.125 moles

Molar mass of

Putting values in equation 1, we get:

Hence, the mass of produced will be 17.8 grams.