During a laboratory experiment, a 3.24-gram sample of nahco3 was thermally decomposed. in this experiment, carbon dioxide and water vapors escape and are combined to form carbonic acid. after decomposition, the sample weighed 2.19 grams. calculate the percentage yield of carbonic acid for the reaction. describe the calculation process in detail. nahco3 → na2co3 + h2co3

Percentage yield of carbonic acid: 88%.

Explanation:

Balance the equation:

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Relative atomic mass data from a modern periodic table:

Formula mass:

Number of moles of NaHCO₃ in the sample:

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How many moles of carbonic acid will that many NaHCO₃ produce in theory? The ratio between the coefficient in front of NaHCO₃ and H₂CO₃ in the balanced equation is 2:1. In other words, it takes two moles of NaHCO₃ to produce one mole of H₂CO₃.

In other words, 0.0385687 moles of NaHCO₃ will produce 0.0192843 moles of H₂CO₃.

What will be the theoretical yield of H₂CO₃?

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What's the actual yield of H₂CO₃?

Mass conserves. As a result, the difference between the mass of the solid before and after the reaction is the mass of the H₂O and CO₂ that escaped. The two species combine to form H₂CO₃. The mass of the H₂CO₃ produced will be the same as the change in the mass of the solid.

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What's the percentage yield of H₂CO₃?

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Note: all values in this question are in 3 sig. fig. Keep more than 3 sig. fig. in the calculations but round the final result to 3 sig. fig.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

i think it is true since you can test the answer and can use observations to complete it.