a chemist reacted 11.50 grams of sodium metal with an excess amount of chlorine gas. the chemical reaction that occurred is shown. na + cl2 → nacl if the percentage yield of the reaction is 85%, what is the actual yield? show your work including, the use of stoichiometric calculations and conversion factors.

24.86 g of sodium chloride

Explanation:

The balanced reaction equation is 2Na(s) + Cl2(g) > 2NaCl(s)

Since chlorine gas was said to be in excess in the question so sodium is the limiting reactant.

From the reaction equation:

46g of sodium metal yields 117g of sodium chloride

11.50g of sodium yields 11.50×117/46 = 29.25g of sodium chloride

Since % yield of sodium chloride= 85%

% yield= actual yield/ theoretical yield ×100

85= actual yield/29.25×100

Actual yield= 85×29.25/100

Actual yield= 24.86 g of sodium chloride

fe 55.85 g/mol and h2o 18.02 g/mol.