What is the mass of 3.0 x 10^23 atoms of neon

Explanation:

Formula

No.of atoms =

G.mass/atomic mass of neon ×6.022×10^23

Putting the values

Given Mass of neon=

3.0×10^23× 20.17/6.022×10^23

=10.048 grams

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol