4.0 liters of helium gas are stored at 125 atm pressure. if the temperature and number of particles do not change. what will be the new volume when the pressure is described at 50atm?

= 10 Liters

Explanation:

According to Boyle's law, the volume of a fixed mass of a gas is inversely proportion to the pressure at constant temperature;

Therefore; V α 1/P, thus, k = PV

For two points of different volume and pressure; P1V1 =P2V2

Hence;

P1V1 = P2V2

4.0 L× 125 atm = V2 × 50 atm

V2 = 500/50

     = 10 L

Thus, the new volume is 10 L

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