What is the minimum amount of 6.0 m h2so4 necessary to produce 15.0 g of h2(g) according to the reaction? 2al(s)+3h2so4(aq)→al2(so4)3(aq)+3h2 (g)

1.25 Liters of 6.0 m solution sulfuric acid is required.

Explanation:

Moles of hydrogen gas =

According to reaction, 3 moles of hydrogen gas are obtained from 3 moles of sulfuric acid.

Then 7.5 moles of hydrogen will be obtained from:

Moles of Sulfuric acid : 7.5 mol

Molarity of the sulfuric acid solution = 6.0 M

Volume of the solution = V

where is the following

explanation:

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