What is the oh in a solution made by adding 0.060 mole of calcium oxide to 500.0ml

0.24 mol/L.

Explanation:

Ca(OH)₂ → Ca²⁺ + 2OH⁻.

Every 1.0 mol of Ca(OH)₂ dissociates to give 2.0 moles of OH⁻.

∴ The no. of moles of OH⁻ produced from 0.06 mol of Ca(OH)₂ = (2 x 0.06 mol) = 0.12 mol.

∴ [OH⁻] = no. of moles / V of the solution = (0.12 mol)/(0.5 L) = 0.24 mol/L.

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