Chemistry, 20.11.2019 22:31 kromaug1517

How many milliliters of 0.100 m naoh are required to neutralize the following solutions?

a.) 10.0 ml of 0.0500 m hcl
b.) 25.0 ml of 0.126 m hno3
c.) 50.0 ml of 0.215 m h2so4

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Answer from: nemorinavory3832

Answers:

a.) 10.0 mL of 0.0500 M HCl: 5.00 mlb.) 25.0 mL of 0.126 M HNO₃: 31.5 mlc.) 50.0 mL of 0.215 M H₂SO4: 215. ml

Explanation:

All the reactions are the neutralization of strong acids with the same strong base.

At the neutralization point you have:

number of equivalents of the base = number of equivalent of the acid

And the number of equivalents (#EQ) may be calculated using the normality (N) concentration and the volume (V)

# EQ = N × V

Then, at the neutralization point:

# EQ acid = N acid × V acid# EQ base = N base × V base# EQ acid = # EQ baseN acid × V acid = N base × V base

Also, you can use the formula that relates normality with molarity

N = M × number of hydrogen or hydroxide ions

a.) 10.0 mL of 0.0500 M HCl

The number of hydrogen ions for HCl is 1 and the number of hydroxide ions for NaOH is 1.10.0 ml × 0.0500 M × 1 = V base × 0.100 M × 1

⇒ V base = 10.0 ml ×0.0500 M / 0.100 M = 5.00 ml

b.) 25.0 mL of 0.126 M HNO₃

The number of hydrogen ions for HNO₃ is 1 and the number of hydroxide ions for NaOH is 1.25.0 ml × 0.126 M × 1 = V base × 0.100 M × 1

⇒ V base = 25.0 ml ×0.126 M / 0.100 M = 31.5 ml

c.) 50.0 mL of 0.215 M H₂SO4

The number of hydrogen ions for H₂SO4 is 2 and the number of hydroxide ions for NaOH is 1.50.0 ml × 0.215 M × 2 = V base × 0.100 M × 1

⇒ V base = 50.0 ml ×0.215 M × 2 / 0.100 M = 215. ml

Answer from: Quest

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

Answer from: Quest

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1

0.44 / 0.09 = 4.8

mgco3-5h2o"

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How many milliliters of 0.100 m naoh are required to neutralize the following solutions?

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