How much energy is required to heat a chunk of ice that weighs 510g from -256°c to 195°c

The ice undergoes several transformations. First it absorbs energy and its temperature to raise the temperature to 0°C the melting point of water. Then the ice absorbs latent heat of fusion to melt, then absorbs heat to raise the temperature to 100°C the boiling point of water. then the steam is heated to 195°C

Therefore the following expression is used to calculate the heat required to make these changes

MC∅(ice)+MLf(ice)+MC∅(water)+MLv(water)+MC∅(water vapor)

0.51kg×2.108kJ/KgK×(0--256)K+0.51×333.55kJ/Kg+0.51kg×4.2 kJ/KgK×(100-0)+0.51kg×2260kJ/kg+ 0.51kg×1.996kJ/kgK× (195-100)K

= 1908.84kJ

h let me think

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.