In a calorimeter, 1.0 kg of ice melts at 0c. the enthalpy of fusion of the ice is 334 j/g. how much heat was absorbed?

= 334 kJ

Given: 1 kg or 1000 g of ice melts at 0°C.

The enthalpy of fusion of the ice is 334 J/g

We know that; Quantity of heat absorbed = mLf

Therefore

Q = (1000 g) (334 J/g)

   = 334,000 J

334,000 J * 1kJ/1000J

  = 334 kJ

In a calorimeter, 100 g of ice melts at 0oC. The enthalpy of fusion of the ice is 334 J/g.

How much heat was absorbed?

-33.4 J

-334 kJ

-334 J

-33.4 kJ  (THIS IS THE ANSWER )

you can do it

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.