Calorimeter containing 1000 grans of water the initial temperature of water is 24.85 degrees . the heat of water is 4.184 j/g degrees the heat capacity of the calorimeter is 695 j/ c after the reaction the final temperature of the water is 35.65

calculate the change of temperature

10.80 ° C

From the information given;

Initial temperature of water =  24.85°C

Final temperature of water = 35.65°C

Mass of water = 1000 g

The specific heat of water ,c = 4.184 J/g °C.

The heat capacity of the calorimeter  = 695 J/ °C

Change in temperature ΔT = 35.65°C - 24.85°C

                                             = 10.80°C

i think   the answer is c hope i'm right