What is the molarity of a solution prepared by dissolving 33.4 g of sodium chloride in some water and then diluting the solution to a volume of 300.00 ml?

1. Since you must need the value for moles to find the molarity you have to convert 33.4g into moles.

33.4gNaCl / 58.44gNaCl = .572molNaCl

2. Since you cannot use mL to find molarity, you must convert the value into liters by dividing the value by 1000.

300.00 / 1000 = .3L

3. Now plug in your values into the equation. ( M = mol/L) [ Just divide moles by the liters]

M = .572 / .300 = 1.91M  OR  1.91mol/L (Units can be M, or mol/L)

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.